Optimal. Leaf size=138 \[ \frac {\log (\cos (c+d x))}{a^2 d}+\frac {\log (1-\sec (c+d x))}{2 (a+b)^2 d}+\frac {\log (1+\sec (c+d x))}{2 (a-b)^2 d}-\frac {b^2 \left (3 a^2-b^2\right ) \log (a+b \sec (c+d x))}{a^2 \left (a^2-b^2\right )^2 d}+\frac {b^2}{a \left (a^2-b^2\right ) d (a+b \sec (c+d x))} \]
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Rubi [A]
time = 0.10, antiderivative size = 138, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {3970, 908}
\begin {gather*} \frac {b^2}{a d \left (a^2-b^2\right ) (a+b \sec (c+d x))}-\frac {b^2 \left (3 a^2-b^2\right ) \log (a+b \sec (c+d x))}{a^2 d \left (a^2-b^2\right )^2}+\frac {\log (\cos (c+d x))}{a^2 d}+\frac {\log (1-\sec (c+d x))}{2 d (a+b)^2}+\frac {\log (\sec (c+d x)+1)}{2 d (a-b)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 908
Rule 3970
Rubi steps
\begin {align*} \int \frac {\cot (c+d x)}{(a+b \sec (c+d x))^2} \, dx &=-\frac {b^2 \text {Subst}\left (\int \frac {1}{x (a+x)^2 \left (b^2-x^2\right )} \, dx,x,b \sec (c+d x)\right )}{d}\\ &=-\frac {b^2 \text {Subst}\left (\int \left (\frac {1}{2 b^2 (a+b)^2 (b-x)}+\frac {1}{a^2 b^2 x}+\frac {1}{a (a-b) (a+b) (a+x)^2}+\frac {3 a^2-b^2}{a^2 (a-b)^2 (a+b)^2 (a+x)}-\frac {1}{2 (a-b)^2 b^2 (b+x)}\right ) \, dx,x,b \sec (c+d x)\right )}{d}\\ &=\frac {\log (\cos (c+d x))}{a^2 d}+\frac {\log (1-\sec (c+d x))}{2 (a+b)^2 d}+\frac {\log (1+\sec (c+d x))}{2 (a-b)^2 d}-\frac {b^2 \left (3 a^2-b^2\right ) \log (a+b \sec (c+d x))}{a^2 \left (a^2-b^2\right )^2 d}+\frac {b^2}{a \left (a^2-b^2\right ) d (a+b \sec (c+d x))}\\ \end {align*}
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Mathematica [A]
time = 0.37, size = 189, normalized size = 1.37 \begin {gather*} \frac {a \cos (c+d x) \left (a^2 (a+b)^2 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )+\left (-3 a^2 b^2+b^4\right ) \log (b+a \cos (c+d x))+a^2 (a-b)^2 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+b \left (a^2 (a+b)^2 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )+\left (-3 a^2 b^2+b^4\right ) \log (b+a \cos (c+d x))+(a-b) \left (-b^2 (a+b)+a^2 (a-b) \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )\right )}{a^2 (a-b)^2 (a+b)^2 d (b+a \cos (c+d x))} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.16, size = 114, normalized size = 0.83
method | result | size |
derivativedivides | \(\frac {-\frac {b^{3}}{a^{2} \left (a +b \right ) \left (a -b \right ) \left (b +a \cos \left (d x +c \right )\right )}-\frac {b^{2} \left (3 a^{2}-b^{2}\right ) \ln \left (b +a \cos \left (d x +c \right )\right )}{\left (a +b \right )^{2} \left (a -b \right )^{2} a^{2}}+\frac {\ln \left (-1+\cos \left (d x +c \right )\right )}{2 \left (a +b \right )^{2}}+\frac {\ln \left (1+\cos \left (d x +c \right )\right )}{2 \left (a -b \right )^{2}}}{d}\) | \(114\) |
default | \(\frac {-\frac {b^{3}}{a^{2} \left (a +b \right ) \left (a -b \right ) \left (b +a \cos \left (d x +c \right )\right )}-\frac {b^{2} \left (3 a^{2}-b^{2}\right ) \ln \left (b +a \cos \left (d x +c \right )\right )}{\left (a +b \right )^{2} \left (a -b \right )^{2} a^{2}}+\frac {\ln \left (-1+\cos \left (d x +c \right )\right )}{2 \left (a +b \right )^{2}}+\frac {\ln \left (1+\cos \left (d x +c \right )\right )}{2 \left (a -b \right )^{2}}}{d}\) | \(114\) |
risch | \(\frac {i x}{a^{2}}-\frac {i x}{a^{2}-2 b a +b^{2}}-\frac {i c}{d \left (a^{2}-2 b a +b^{2}\right )}-\frac {i x}{a^{2}+2 b a +b^{2}}-\frac {i c}{d \left (a^{2}+2 b a +b^{2}\right )}+\frac {6 i b^{2} x}{a^{4}-2 b^{2} a^{2}+b^{4}}+\frac {6 i b^{2} c}{d \left (a^{4}-2 b^{2} a^{2}+b^{4}\right )}-\frac {2 i b^{4} x}{a^{2} \left (a^{4}-2 b^{2} a^{2}+b^{4}\right )}-\frac {2 i b^{4} c}{a^{2} d \left (a^{4}-2 b^{2} a^{2}+b^{4}\right )}+\frac {2 b^{3} {\mathrm e}^{i \left (d x +c \right )}}{a^{2} d \left (-a^{2}+b^{2}\right ) \left (a \,{\mathrm e}^{2 i \left (d x +c \right )}+2 b \,{\mathrm e}^{i \left (d x +c \right )}+a \right )}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d \left (a^{2}-2 b a +b^{2}\right )}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d \left (a^{2}+2 b a +b^{2}\right )}-\frac {3 b^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+\frac {2 b \,{\mathrm e}^{i \left (d x +c \right )}}{a}+1\right )}{d \left (a^{4}-2 b^{2} a^{2}+b^{4}\right )}+\frac {b^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+\frac {2 b \,{\mathrm e}^{i \left (d x +c \right )}}{a}+1\right )}{a^{2} d \left (a^{4}-2 b^{2} a^{2}+b^{4}\right )}\) | \(413\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 142, normalized size = 1.03 \begin {gather*} -\frac {\frac {2 \, b^{3}}{a^{4} b - a^{2} b^{3} + {\left (a^{5} - a^{3} b^{2}\right )} \cos \left (d x + c\right )} + \frac {2 \, {\left (3 \, a^{2} b^{2} - b^{4}\right )} \log \left (a \cos \left (d x + c\right ) + b\right )}{a^{6} - 2 \, a^{4} b^{2} + a^{2} b^{4}} - \frac {\log \left (\cos \left (d x + c\right ) + 1\right )}{a^{2} - 2 \, a b + b^{2}} - \frac {\log \left (\cos \left (d x + c\right ) - 1\right )}{a^{2} + 2 \, a b + b^{2}}}{2 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.34, size = 234, normalized size = 1.70 \begin {gather*} -\frac {2 \, a^{2} b^{3} - 2 \, b^{5} + 2 \, {\left (3 \, a^{2} b^{3} - b^{5} + {\left (3 \, a^{3} b^{2} - a b^{4}\right )} \cos \left (d x + c\right )\right )} \log \left (a \cos \left (d x + c\right ) + b\right ) - {\left (a^{4} b + 2 \, a^{3} b^{2} + a^{2} b^{3} + {\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} \cos \left (d x + c\right )\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) - {\left (a^{4} b - 2 \, a^{3} b^{2} + a^{2} b^{3} + {\left (a^{5} - 2 \, a^{4} b + a^{3} b^{2}\right )} \cos \left (d x + c\right )\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right )}{2 \, {\left ({\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d \cos \left (d x + c\right ) + {\left (a^{6} b - 2 \, a^{4} b^{3} + a^{2} b^{5}\right )} d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\cot {\left (c + d x \right )}}{\left (a + b \sec {\left (c + d x \right )}\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 303 vs.
\(2 (134) = 268\).
time = 0.51, size = 303, normalized size = 2.20 \begin {gather*} -\frac {\frac {2 \, {\left (3 \, a^{2} b^{2} - b^{4}\right )} \log \left ({\left | -a - b - \frac {a {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {b {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} \right |}\right )}{a^{6} - 2 \, a^{4} b^{2} + a^{2} b^{4}} - \frac {\log \left (\frac {{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right )}{a^{2} + 2 \, a b + b^{2}} - \frac {2 \, {\left (3 \, a^{2} b^{2} + 4 \, a b^{3} + b^{4} + \frac {3 \, a^{2} b^{2} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} - \frac {b^{4} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1}\right )}}{{\left (a^{5} + a^{4} b - a^{3} b^{2} - a^{2} b^{3}\right )} {\left (a + b + \frac {a {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} - \frac {b {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1}\right )}} + \frac {2 \, \log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1 \right |}\right )}{a^{2}}}{2 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.98, size = 160, normalized size = 1.16 \begin {gather*} \frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d\,\left (a^2+2\,a\,b+b^2\right )}-\frac {\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{a^2\,d}-\frac {b^2\,\ln \left (a+b-a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\right )\,\left (3\,a^2-b^2\right )}{a^2\,d\,{\left (a^2-b^2\right )}^2}-\frac {2\,b^3}{a\,d\,\left (a+b\right )\,{\left (a-b\right )}^2\,\left (\left (b-a\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+a+b\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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